16x^2-104x=-25

Solution for 16x^2-104x=-25 equation:

16x^2-104x=-25

We move all terms to the left:

16x^2-104x-(-25)=0

We add all the numbers together, and all the variables

16x^2-104x+25=0

a = 16; b = -104; c = +25;
Δ = b2-4ac
Δ = -1042-4·16·25
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-96}{2*16}=\frac{8}{32}
=1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+96}{2*16}=\frac{200}{32}
=6+1/4
$